Question

I have a PHP script to echo the contents of a Mysql table.
I’m using it as a small CMS for a static page.

What I want to know is how can I go about displaying an Image in my PHP script.
I have a form that submits the Date, Title, Message, and Image.

I’m using the Image field to insert the URL of an image.
Whats the correct way of displaying the image on a page.

Below is my code:

<?php
$con = mysql_connect("localhost","name","password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("databaseName", $con);

$result = mysql_query("SELECT * FROM Blog");


while($row = mysql_fetch_array($result))
  {
  echo $row['Date'];
  echo "<br />";
  echo $row['Title'];
  echo "<br />";
  echo $row['Message'];
  echo "<br />";
  echo $row['Image'];
  echo "<br />";
  echo "<br />";
  echo "<br />";
  }

mysql_close($con);
?>

This is the outcome:

17th Feb
Title
Here is my Message
http‍://vickybeeching.com/blog/wp-content/uploads/2011/09/canthearyou.jpeg

18th Feb
Title
Here is my Message
http‍://vickybeeching.com/blog/wp-content/uploads/2011/09/canthearyou.jpeg

but I want the page to display the image not the URL.
I’m guessing just using the <img></img> tags, but I’m not sure where in the PHP.

Answer 1

You can write code in image tag instead of echo directly.

Try this code.

echo "<img src='".$row['Image']."'/>";