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Home/ Questions/Q 6382585
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T02:32:29+00:00 2026-05-25T02:32:29+00:00

I have a piece of code for(int i = 0; i < num_of_random; i++){

  • 0

I have a piece of code

for(int i = 0; i < num_of_random; i++){

    String str = in.readLine();
    if(str != null){
        String[] randoms = new String[4];
        randoms = str.split(",");

        dateRanges[i] = Integer.parseInt(randoms[0]);
        id[i] = Integer.parseInt(randoms[1]);
        flag[i] = Integer.parseInt(randoms[2]);
        system[i] = Integer.parseInt(randoms[3]);
    }
}

When I run this code against findBugs, I get a suggestion for

“String[] randoms = new String[4];”

This instruction assigns a value to a local variable, but the value is not read or used in any subsequent instruction. Often, this indicates an error, because the value computed is never used.

Why do I get this?

Thanks a lot

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  1. Editorial Team
    Editorial Team
    2026-05-25T02:32:30+00:00Added an answer on May 25, 2026 at 2:32 am

    Because you initialize a variable to a value (new String[4]), and then replace the variable value with another one (the result of str.split(",")) just after. The initialization is thus not necessary.

    Your code is functionally equivalent to

    String[] randoms = str.split(",");
    

    except it allocates a new String array which is immediately discarded.

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