Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I have a piece of code getting the roots of an integer. I would like these roots to be rounded to something like 2 or 3 DP.
But Math.sqrt() (and eqivs for other roots) gives an automatically rounded square root.
I have done a bit of reaseach, and can’t find a simple way of getting this. I don’t really want to have to switch to another way, got to a library or anything else, Math.sqrt() is a nice easy way, just rounds it. Can I do this?
“rounded” here doesn’t mean “rounded to integer value”; from the API: “the result is the double value closest to the true mathematical square root of the argument value”.