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Home/ Questions/Q 7741965
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T09:09:45+00:00 2026-06-01T09:09:45+00:00

I have a piece of code like so… FileInputStream fi = new FileInputStream(filein); GZIPInputStream

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I have a piece of code like so…

FileInputStream fi = new FileInputStream(filein);
GZIPInputStream gzis = new GZIPInputStream(fi);
ByteBuffer bbuffer = ByteBuffer.allocate(115200);

The fi.available() is 84300, but the gzis.available() is only 1. The file(filein) is already compressed.

I want to read the file, uncompress it, and finally put it into my ByteBuffer bbufer.

How could I realize this operation?

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  1. Editorial Team
    Editorial Team
    2026-06-01T09:09:47+00:00Added an answer on June 1, 2026 at 9:09 am

    gzis.available() = 1; doesn’t mean that there is a problem, it simply means that you can only read 1 byte of information from the Stream before you can continue. you can’t expect that the entire uncompressed file will be available in a single command.

    To read the entire file, you will need to have a loop that continues to read over the InputStream until you have all the data. For example…

    int bytesRead = 0;
    int bytesAvailable = gzis.available();
    while (bytesAvailable > 0){
        gzis.read(bbuffer,bytesRead,bytesAvailable);
        bytesRead += bytesAvailable;
        bytesAvailable = gzis.available();
    }
    

    Of course, if you aren’t sure of the final size of the uncompressed file, you’ll need to add in extra code to allow your bbuffer to be resized if you need more room.

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