Question

I have a piece of code that looks like this:

$result = mysql_query($queryc) or die(mysql_error());   

if(mysql_num_rows($result) > 0)                             
{   
  while($row = mysql_fetch_array($result, MYSQL_ASSOC))
  {
    echo $row['$field']; 
  }
}

Say that code was in a function and I wanted to pass $field to the $row[”] how would I accomplish that?

In other words I’m attempting to use $row[‘$field’]; and $field is defined elsewhere

Answer 1

suppose you have this function definition:

function foo($field) {
    // from that code you have given
    ....
    echo $row[$field];  // no need of the quotation marks around $field
    ....
}