Question

I have a piece of code to be understood. But I’m lost in one point.
Here is the code:

typedef unordered_map <string, TimeStampSet *> HIEMap;
typedef set <TimeStamp> TimeStampSet;

struct HostInfo {
    HostActivity *hostActivity;
    HIEMap *hieMapArr;
};

typedef unordered_map <uint32_t, HostInfo *> HostInfoMap;

HIEMap::iterator hieMapIt;

void method(...){
    for (hieMapIt = hostInfoIt -> second -> hieMapArr -> begin();
         hieMapIt != hostInfoIt -> second -> hieMapArr -> end();
         hieMapIt = nextMapIt)
    {
        if (hieMapIt -> second == NULL) {
           //what does *hieMapIt -> second* returns?
        }
    }
}

What does hieMapIt -> second return? I’ m a bit lost.

This is not all code, there are initializations and so on. But I dont put all the code here.

Thanks,

Answer 1

It will return a TimeStampSet *. That is, the second part of the unordered_map (string , TimeStampSet *) “pair”.