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Home/ Questions/Q 5932625
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T14:51:37+00:00 2026-05-22T14:51:37+00:00

I have a pointer and I want to assign the bytes from x to

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I have a pointer and I want to assign the bytes from x to (x+1) to a unsigned short. I was hoping that I could just

(unsigned short) pointer[x]

but the first byte seems to always be empty. But when I check the value of bytes x and x+1 individually the data is there.

Where have I noobed? (I just made it a verb)

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  1. Editorial Team
    Editorial Team
    2026-05-22T14:51:37+00:00Added an answer on May 22, 2026 at 2:51 pm
    unsigned short i = (pointer[x] << 8) + pointer[x+1]
    

    Assuming you want x to be the high bits and x+1 to be the low bits. Actually, you should keep endianness in mind here too.

    EDIT:

    This may also work:

    *(unsigned short *) pointer[x]
    

    However, this will be affected by endianness, for example, in little endian the first byte will be the lower 8 bits, while x+1 will be the higher bytes.

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