Question

I have a pointer to a character array:

space=(char**)calloc(100000,sizeof(char*));
for(i=0;i<100000;i++){
    space[i]=(char*)calloc(1,sizeof(char));
}

such that when I use the following command

printf("%s\n",space[0]);

I get "a b c d e"

I want to assign "a b c d e" to

char c[10];

such that

printf("%s",c) yields

"a b c d e"

but when I try

c=space[0]

I get the following error:

incompatible types in assignment

What am I doing wrong?

Answer 1

First, you need to allocate enough space to hold the entire string at location space[0]. Currently you are allocating a single character.
After you do that you would use strcpy() to copy the string into the newly allocated buffer.

space=(char**)calloc(100000,sizeof(char*));
...
space[0]=(char*)calloc(10,sizeof(char));
strcpy(space[0], "a b c d e");

PS: Don’t forget to free() any prior allocated strings at space[0] (like the one you create in the for() loop) before you allocate for the new string. Or you could use realloc() instead.