Question

I have a pom.xml that uses cxf-codegen-plugin to generate a couple of WS clients.

Inside the configuration of cxf-codegen-plugin, there are the WSDL locations.

I would like to externalize those strings to a env.properties file.

I used org.codehaus.mojo’s properties-maven-plugin to look inside src/main/resources/conf/app/env.properties.

How can I make Hudson to replace those properties with the apropiate host?

Thanks in advance

Answer 1

Filtering and profiles should work.

Setup a husdon filter file and place in src/main/filters. Create an additional filter file for each region you need to run in.

The filter files should be named similarly, like so: filter-hudson.properties, filter-prod.properties, etc. and contain the same properties:

wsdl.host=myHost
etc...

Then have simple profiles that contain the environment you run on:

<profiles>
  <profile>
    <id>prod</id>
    <properties>
      <env>prod</env>
    </properties>
  </profile>
  <profile>
    <id>hudson</id>
    <properties>
      <env>hudson</env>
    </properties>
  </profile>
</profiles>

If you then setup your filters in your pom:

<filters>
  <filter>src/main/filters/filter-${env}.properties</filter>
</filters>
<resources>
  <resource>
    <directory>src/main/resources/conf/app</directory>
    <filtering>true</filtering>
  </resource>
</resources>

Then the files in conf app will have wsdl.host replaced with the specific values in your filter.

Then when you run your hudson build, add -P hudson to invoke the hudson profile.

There may be a “better” way to do this, but about a year and a half ago, I had success with this technique. To give proper credit, here’s the blog post I used as instructions.