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Asked: May 11, 20262026-05-11T03:40:02+00:00 2026-05-11T03:40:02+00:00

I have a portion of a bash script that is getting a filename without

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I have a portion of a bash script that is getting a filename without extension, but I’m trying to understand what is really going on here. What are the ‘%%”s for? Can someone elaborate on what bash is doing behind the scenes? How can this technique be used on a general basis?

#!/bin/bash  for src in *.tif     do     txt=${src%%.*}     tesseract ${src} ${txt}     done 
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  1. 2026-05-11T03:40:03+00:00Added an answer on May 11, 2026 at 3:40 am

    It gets rid of the filename extension (here: .tif), sample:

    $ for A in test.py test.sh test.xml test.xsl; do echo '$A: ${A%%.*}'; done test.py: test test.sh: test test.xml: test test.xsl: test 

    from bash manual:

       ${parameter%%word}           The word is expanded to produce a pattern just as in pathname expansion.  If the           pattern matches a trailing portion of the expanded value of parameter, then  the           result  of  the  expansion  is the expanded value of parameter with the shortest           matching pattern (the ``%'' case) or the longest matching  pattern  (the  ``%%''           case) deleted.  If parameter is @ or *, the pattern removal operation is applied           to each positional parameter in turn, and the expansion is the  resultant  list.           If  parameter  is an array variable subscripted with @ or *, the pattern removal           operation is applied to each member of the array in turn, and the  expansion  is           the resultant list. 
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