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Home/ Questions/Q 6657275
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T01:44:51+00:00 2026-05-26T01:44:51+00:00

I have a preprocessor macro defined in build settings FOO=BAR That value I want

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I have a preprocessor macro defined in build settings

FOO=BAR

That value I want to massage into an Objective-C string literal that can be passed to a method. The following #define does not work, but it should demonstrate what I am trying to achieve:

 #define FOOLITERAL @"FOO" //want FOOLITERAL to have the value of @"BAR"

 myMethodThatTakesAnNSString(FOOLITERAL);

I expect that I am just missing the obvious somehow, but I cannot seem to find the right preprocessor voodoo to get what I need.

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  1. Editorial Team
    Editorial Team
    2026-05-26T01:44:52+00:00Added an answer on May 26, 2026 at 1:44 am

    Use the stringizing operator # to make a C string out of the symbol. However, due to a quirk of the preprocessor, you need to use two extra layers of macros:

    #define FOO BAR
    #define STRINGIZE(x) #x
    #define STRINGIZE2(x) STRINGIZE(x)
    #define FOOLITERAL @ STRINGIZE2(FOO)
    // FOOLITERAL now expands to @"BAR" 
    

    The reason for the extra layers is that the stringizing operator can only be used on the arguments of the macro, not on other tokens. Secondly, if an argument of a macro has the stringizing operator applied to it in the body of the macro, then that argument is not expanded as another macro. So, to ensure that FOO gets expanded, we wrap in another macro, so that when STRINGIZE2 gets expanded, it also expands FOO because the stringizing operator does not appear in that macro’s body.

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