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Editorial Team
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Asked: 2026-06-13T19:29:36+00:00

I have a pretty basic forum template I am working on for testing purposes

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I have a pretty basic forum template I am working on for testing purposes

When I create a topic, and press submit, the proccess updates the database but doesn’t output on the screen. Why is this? and Why am I getting a Resource id #4 when I echo the $result from this code below:

<?php

$host="server"; // Host name 
$username="usernamehere"; // Mysql username 
$password=""; // Mysql password 
$db_name="forum"; // Database name 
$tbl_name="question"; // Table name 

// Connect to server and select databse.
mysql_connect("$host", "$username", "")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");
$sql="SELECT * FROM $tbl_name ORDER BY id DESC";
// OREDER BY id DESC is order result by descending

$result=mysql_query($sql);
echo $result;
?>
<html>
<body>
<table width="90%" border="0" align="center" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC">
<tr>
<td width="6%" align="center" bgcolor="#E6E6E6"><strong>#</strong></td>
<td width="53%" align="center" bgcolor="#E6E6E6"><strong>Topic</strong></td>
<td width="15%" align="center" bgcolor="#E6E6E6"><strong>Views</strong></td>
<td width="13%" align="center" bgcolor="#E6E6E6"><strong>Replies</strong></td>
<td width="13%" align="center" bgcolor="#E6E6E6"><strong>Date/Time</strong></td>
</tr>

<?php

// Start looping table row
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td>
<td bgcolor="#FFFFFF"><a href="view_topic.php?id=<? echo $rows['id']; ?>"><? echo $rows['topic']; ?></a><BR></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['view']; ?></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['reply']; ?></td>
<td align="center" bgcolor="#FFFFFF"><? echo $rows['datetime']; ?></td>
</tr>

<?php
// Exit looping and close connection 
}
mysql_close();
?>

<tr>
<td colspan="5" align="right" bgcolor="#E6E6E6"><a href="create_topic.php"><strong>Create New Topic</strong> </a></td>
</tr>
</table>
</body>
</html>
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1 Answer

  1. Editorial Team

    You are getting resource id #4 because $result is an resource,you must extract the values contained in it by this way,

    $result=mysql_query($sql);
$values = mysql_fetch_array($result);
var_dump($values);

    More about resource variable

    Update 2(From OP comments)

    You are printing values using field name,In that case you will have to change to

    while($rows=mysql_fetch_array($result,MYSQL_ASSOC))

    Or you can directly use mysql_fetch_assoc(),which in your case will be

    while($rows=mysql_fetch_assoc($result)){
      echo $rows['id'];
}
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