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Home/ Questions/Q 8419891
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T02:44:28+00:00 2026-06-10T02:44:28+00:00

I have a pretty easy structure: var FORMS = []; function FormObject(type) { this.FormId

  • 0

I have a pretty easy structure:

var FORMS = [];

function FormObject(type)
{
    this.FormId = FORMS.length;
    //alert(this.FormId); returns results 0 and 1 respectively.
    this.Type = type;
    FORMS.push(FormObject); 
    this.generate = generate();
}

function generate()
{
    return 5;
}

Then I do something like this:

var new_form = new FormObject('fruit');
var another  = new FormObject('vegetable');
alert(another.FormId);//as expected, I get 1 as a result

And then finally try do something like this:

alert(FORMS.length);//result is 2 so I assume the objects got created successfully
alert(FORMS[0]);//prints the whole code of the constructor into the dialog box

However when I try something like this:

alert(FORMS[0].FormId);//result is undefined!!!
alert(FORMS[0].generate());//it shows an error that the object does not have such method

Why is it undefined? I tried reading http://javascript.crockford.com/private.html and it says:

Patterns

Public

function Constructor(...) {
    this.membername = value;
}
Constructor.prototype.membername = value;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T02:44:30+00:00Added an answer on June 10, 2026 at 2:44 am

    Replace:

    FORMS.push(FormObject); 
    

    with

    FORMS.push(this);
    

    When you push the FormObject object, you are pushing the constructor function, not the instance.

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