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Home/ Questions/Q 3456042
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T09:41:17+00:00 2026-05-18T09:41:17+00:00

I have a pretty limited experience with AJAX and javascript so hopefully this is

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I have a pretty limited experience with AJAX and javascript so hopefully this is easier than it’s been for me.
I’m building a simple upload form, just sending data from a form and then to the js then send that over to the php.
basically in the html (which is generated from a php page):

<form id="form" method="post" onsubmit="return ajaxSubmit(this)" action="#">
<input name="data1" type="file"/>
<input type="submit" value="Go"/>

and the js:

function ajaxSubmit(thisform) { 
    results=GetXmlHttpObject();
    var submitdata ="";
    submitdata = "uploadfile=" + thisform.elements['data1'].value
results.onreadystatechange=uploadResult; 
    results.open("POST", "./functions/upload.php",true);
    results.send(formdata);

(i’ve stripped out some of the code to make it shorter)
I need to also send a php variable through, so I imagine I could write the function call as onsubmit=”return songUploadSubmit(this, “.$phpvariable.”) but I don’t know how to pull it out on the javascript end. I need to know, simply I guess, how to pull $phpvariable and tack it on the end of submitdata variable. or if i’m going about this backwards..
Thankyou!

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  1. Editorial Team
    Editorial Team
    2026-05-18T09:41:18+00:00Added an answer on May 18, 2026 at 9:41 am

    Got it to work:

    in html:

     return ajaxSubmit(this, $phpvariable)
    

    in jscript:

    function songUploadSubmit(thisform, otherdata)
    submitdata = "data1=" + thisform.elements['data1'].value + "&data2=" + otherdata;
    

    then I can grab both with _Post in the php file.

    Overall just basic missing of some fundamentals like I suspected it might be. Passing multiple arguments.

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