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Home/ Questions/Q 6160003
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:13:33+00:00 2026-05-23T21:13:33+00:00

I have a pretty simple scenario. I have the following HTML: <h1>Hello</h1> <input type="button"

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I have a pretty simple scenario. I have the following HTML:

<h1>Hello</h1>
<input type="button" value="Change" id="change" />

With the corresponding JS:

var h1 = $("h1").get(0);

h1.addEventListener("DOMSubtreeModified", function(ev) {

    console.log("Changed");
    
    ev.bubbles = false;
    ev.cancelBubble = true;
    ev.defaultPrevented = true;
    ev.preventDefault();
    ev.stopPropagation();
    ev.returnValue = false;
    
    return false;
    
}, false);

$("#change").click(function() {
    $("h1").text("World");
});

So, this basically just changes the text of the H1 node and the event is then fired. However, the event is firing twice (as I assume as a result of bubbling). As you can see, I’ve tried throwing everything at it to try to get it to not fire twice, but that does not stop it. If you want to play with the code, you can check it out at: http://jsfiddle.net/sECtq/. Any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-23T21:13:34+00:00Added an answer on May 23, 2026 at 9:13 pm

    This behaviour is not caused by bubbling.

    $.text() executes 2 steps to set the new text:

    1. remove the existing contents
    2. insert a new textNode

    Both steps trigger DOMSubtreeModified, so you get 2 alerts.

    You may use e.g. the following:

    $("h1")[0].firstChild.data="World";
    

    This will only change the contents of the textNode without removing a node.

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