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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T19:47:45+00:00 2026-05-17T19:47:45+00:00

I have a problem about the management of dates with milliseconds. I understand the

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I have a problem about the management of dates with milliseconds. I understand the need to use the TIMESTAMP to store milliseconds:

@Temporal(TIMESTAMP)
@Column(name="DATE_COLUMN", nullable = false)
@Override public java.util.Date getDate() { return this.date; }

But if I can’t compare this date to another instance of java.util.Date, unless I pay attention to the order of equals() call, because this.date instance is a java.sql.Timestamp. How to get a java.util.Date from JPA ? Because the date that comes from JPA, even if the method signature is a java.util.Date is actually an instance of java.sql.Timestamp.

java.util.Date newDate = new Date(this.date.getTime());
this.date.equals(newDate) == false
newDate.equals(this.date) == true

I’ve try to modify my method in the persistence class:

@Override
public Date getDate() {
  return this.date == null ? null : new Date(this.date.getTime());
}

It’s working, but it’s not efficient with lots of data.

There are other options :

  • I could modify the design of my persistence class, using @PostLoad in order to create a java.util.Date from the persited date after I retrieve it.

  • I wonder if I can not get a result using a ClassTransformer?

Have you ever been confronted with this problem? What I do not correctly? What is the best way to handle this problem?

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  1. Editorial Team
    Editorial Team
    2026-05-17T19:47:46+00:00Added an answer on May 17, 2026 at 7:47 pm

    java.sql.Timestamp overrides the compareTo(Date) method, so it should be no problem using compareTo(..)

    In short – java.util.Date and java.sql.Timestamp are mutually comparable.

    Furthermore, you can always compare the date.getTime(), rather than the objects themselves.

    And even further – you can use a long field to store the date. Or even a DateTime (from joda-time)

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