Question

I have a problem and can’t find information.

I run my web-app from jsp-page which find on folder in “web”. And try to go to servlet
Smth like this

<form action="MyServlet" method="post">
            <input type="submit" name="command" />
</form>

In web.xml next

<servlet>
        <servlet-name>MyServlet</servlet-name>
        <servlet-class>mypackage.MyServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>MyServlet</servlet-name>
        <url-pattern>/MyServlet</url-pattern>
</servlet-mapping>

I thought that this should work but when I run my app I see next url for button

But my goal is get url localhost:8080/TomcatApp/MyServlet

I try to do it using GlassFish and Apache Tomcat 7. I don’t know. Can you help me?

Answer 1

The form’s action is relative to the current page’s path. So if your JSP is at /TomcatApp/folder/some-page.jsp, just setting the action to MyServlet is the same as /TomcatApp/folder/MyServlet because it automatically uses the current path as a base. To get just /TomcatApp/MyServlet, you need to set your form’s action to either ../MyServlet or ${request.contextPath}/MyServlet.