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Home/ Questions/Q 7910405
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T12:51:38+00:00 2026-06-03T12:51:38+00:00

I have a problem converting a char array to a unsigned short (UInt16). My

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I have a problem converting a char array to a unsigned short (UInt16). My converting techniques seems to be wrong…
Here is the code:

#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int _tmain(int argc, _TCHAR* argv[])
{
    // Symbols 0x1210 :
    char test[2];
    test[0] = 0x12;
    test[1] = 0x10;

    unsigned short n;
    memcpy(&n, test, sizeof(unsigned short));

    int i=0, arrToInt=0;
    for(i=1;i>=0;i--)
        arrToInt =(arrToInt<<8) | test[i];

    /*
    Now are:

    n = 4114
    arrToInt = 4114

    But! -> 0x1210 == 4624
    */

    return 0;
}

Is there a way (without) reversing the char array?

Thanks for your help!

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  1. Editorial Team
    Editorial Team
    2026-06-03T12:51:41+00:00Added an answer on June 3, 2026 at 12:51 pm
    for(i=0;i<=1;i++)
        arrToInt =(arrToInt<<8) | test[i];
    
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