Question

I Have A problem In displaying JS Code In PHP
My Code Is

<?php
    if($result)
    {
        echo '<script language="javascript">';
        echo "$('#Err').hide()</script>";
    }
    else
    {
        echo '<script language="javascript">';
        echo "$('#Err').show()</script>";
    }
?>

I Am Using XAMPP For running Code When I Run This Code It Will Not Display
I Don’t know what’s the problem
plz tell me
Thanks!

Answer 1

You have to escape the $ sign as follows:

<?php
    if($result)
    {
        echo '<script language="javascript">';
        echo "\$('#Err').hide()</script>";
    }
    else
    {
        echo '<script language="javascript">';
        echo "\$('#Err').show()</script>";
    }
?>