Question

I have a problem in Python.

How can I increment by one fully automatically the -“number” present in this if statement?

An example to understand me. I have this situation

def name1:
    if (dictionary[class.methodclass()][constant - 1] == dictionary[class.methodclass()][constant - 2] == dictionary[class.methodclass()][constant - 3] == ldictionary[class.methodclass()][constant - 4] == dictionary[class.methodclass()][constant - 5]):
        blablabla

def name2:
    if (dictionary[class.methodclass()][constant - 1] == dictionary[class.methodclass()][constant - 2] == dictionary[class.methodclass()][constant - 3] == ldictionary[class.methodclass()][constant - 4]):
        blabla

def name3:
    if (dictionary[class.methodclass()][constant - 1] == dictionary[class.methodclass()][constant - 2] == dictionary[class.methodclass()][constant - 3]):
        blabla

I repeat the same code, so how to avoid this?

Thank you

Edit: I have a normal dictonary like

dictonary = {"Element": ["Key1", "Key2"]}

I wanna have a cycle that confirm me to work with “Key1” == “Key2” case.

Answer 1

This is a way:

if all ( [ dictionary[class.methodclass()][constant - 1] ==  
           dictionary[class.methodclass()][ noConstant]  
           for noConstant in range(constant - 2,  constant - 6, -1 )  ]
       ):
    blablabla