Question

I have a problem passing a variable through into a jquery function:

function showImage(type, top, url) {
$.getJSON('<?php echo $_SERVER['PHP_SELF']?>',{
    type: type,
    top: top,
    img: url,
    action: 'imginfo'    
    }, function(retval) {
        if (retval['isimg']) {
            $('#tdDimensions').html(retval['dimension']);
            $('#thPreview').html(retval['previewtext']);
            alert($('#tdPreview').html());
            alert(img);

This is part of my code, but the problem is that in the success function (function(retval)) I cannot acces the parameters passed to showImage() anymore.

How can I realise this so that the alert(img) in this code will work?

Answer 1

How can I realise this so that the alert(img) in this code will work?

Just use url arg from showImage – your callback, as inner function, has access to it. Read more about closures if you’re not sure why.