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Home/ Questions/Q 4063822
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T15:46:33+00:00 2026-05-20T15:46:33+00:00

I have a problem that I believe I need to use grouping using xsl:key

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I have a problem that I believe I need to use grouping using xsl:key to solve, but I am at a loss as to the correct syntax. For the following XML, when I process each <a/> element I need to test to see if

  1. the element has a preceding-sibling <markerStart/> element and a descendant </markerEnd> element with the same id.

    • By “preceding-sibling” I mean that there must not be an <a/> between the current element and the <markerStart/> , so the <a/> marked <!-- # 5 --> should return false, while the <a/> marked <!-- # 1 --> and the first <a/> following the element marked <!-- # 2a --> should return true.
    • By “descendant” I mean that there must not be an <a/> descendant before the <markerEnd/> , so the <a/> marked <!-- # 0 --> and the first <a/> following the element marked <!-- # 2b --> should return false.
  2. OR the element has a descendant <markerStart/> element and a descendant </markerEnd> element with the same id.

    • By “descendant” I mean that there must not be an <a/> descendant before the <markerEnd/>.

For the following XML, I would expect the nodes marked with <!-- # 1 -->, <!-- # 2a -->, and <!-- # 4 --> to return true.

<root>
    <a><!-- # 0 -->
        <b>
            <c>
                <markerStart id="a1"/>
                <a> <!-- # 1 -->
                    <b>
                        <c>
                        <markeEnd id="a1"/>
                        </c>
                    </b>
                </a>
                <markerStart id="a2"/><!-- # 2a -->
                <markerStart id="a3"/><!-- # 2b -->
                <a><!-- # 2 -->
                    <b>
                        <c>
                        <markeEnd id="a2"/>
                            <a><!-- # 3 -->
                                <b>
                                    <c>
                                        <markeEnd id="a3"/>
                                    </c>
                                </b>
                            </a>
                        </c>
                    </b>
                </a>
                <markerStart id="a5"/>
                <a><!-- # 4 -->
                    <markerStart id="a4"/>
                    <b>
                        <c>
                        <markeEnd id="a4"/>
                        </c>
                    </b>
                </a>
                <a><!-- # 5 -->
                    <b>
                        <c>
                        <markeEnd id="a5"/>
                        </c>
                    </b>
                </a>
            </c>
        </b>
    </a>
</root>

I need to used XSL 1.0 for this problem. Any help is more than appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T15:46:34+00:00Added an answer on May 20, 2026 at 3:46 pm

    This stylesheet:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
        <xsl:key name="kMarkerStartByFollowingMarkeEnd"
                 match="markerStart"
                 use="generate-id(following::markeEnd[1])"/>
        <xsl:key name="kMarkeEndByAncestorA"
                 match="markeEnd"
                 use="generate-id(ancestor::a[1])"/>
        <xsl:template match="a[key('kMarkeEndByAncestorA',
                                   generate-id()
                               )[1]/@id =
                               key('kMarkerStartByFollowingMarkeEnd',
                                   generate-id(key('kMarkeEndByAncestorA',
                                                   generate-id()
                                               )[1])
                               )/@id]">
            <xsl:copy-of select="comment()"/>
            <xsl:apply-templates/>
        </xsl:template>
    </xsl:stylesheet>
    

    Output:

    <!-- # 1 --><!-- # 2 --><!-- # 4 -->
    
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