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Home/ Questions/Q 7774969
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T17:30:41+00:00 2026-06-01T17:30:41+00:00

I have a problem that should be quite common. I have an Array of

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I have a problem that should be quite common. I have an Array of data called taskList this comes from a JSON and has several user data. So far, so good. I make the first objectForKey:@"desc" and returns the result (Description of user) but when I try to add another objectForKey (age for example) it shows only the age 🙁 This is the code:

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{

    UITableViewCell *cell = nil;
    cell = [tableView dequeueReusableCellWithIdentifier:@"MyCell"];

    if (cell == nil){
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"MyCell"] autorelease];
    }

    NSLog(@"%@",taskList);
    cell.textLabel.text = [[taskList objectAtIndex:indexPath.row] objectForKey:@"desc"];
    return cell;
    cell.textLabel.text = [[taskList objectAtIndex:indexPath.row] objectForKey:@"age"];
    return cell;
}
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  1. Editorial Team
    Editorial Team
    2026-06-01T17:30:43+00:00Added an answer on June 1, 2026 at 5:30 pm

    do this instead:

    NSString *desc = [[taskList objectAtIndex:indexPath.row] objectForKey:@"desc"];
    NSString *age  = [[taskList objectAtIndex:indexPath.row] objectForKey:@"age"];
    
    cell.textLabel.text = [desc stringByAppendingString:age];
    return cell;
    

    Another example, which formats the string (in this case the only difference is that I’m adding a space between the two but it introduces you to a very very helpful method) (and uses the two strings that we created above):

    NSString *textForMyLabel = [NSString stringWithFormat:@"%@ %@", desc, age];
    cell.textLabel.text      = textForMyLabel;
    

    Or to do the same thing without the temporary variable textForMyLabel use:

    cell.textLabel.text = [desc stringByAppendingFormat:@" %@", age];
    
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