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Home/ Questions/Q 683183
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:40:44+00:00 2026-05-14T01:40:44+00:00

I have a problem when I try to persist my model. An exception is

  • 0

I have a problem when I try to persist my model. An exception is thrown when creating the EntityManagerFactory:

Blockquote
javax.persistence.PersistenceException: [PersistenceUnit: ASD] Unable to build EntityManagerFactory
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:677)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:126)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:52)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:34)
at project.serealization.util.PersistentManager.createSession(PersistentManager.java:24)
at project.serealization.SerializationTest.testProject(SerializationTest.java:25)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at junit.framework.TestCase.runTest(TestCase.java:168)
at junit.framework.TestCase.runBare(TestCase.java:134)
at junit.framework.TestResult$1.protect(TestResult.java:110)
at junit.framework.TestResult.runProtected(TestResult.java:128)
at junit.framework.TestResult.run(TestResult.java:113)
at junit.framework.TestCase.run(TestCase.java:124)
at junit.framework.TestSuite.runTest(TestSuite.java:232)
at junit.framework.TestSuite.run(TestSuite.java:227)
at org.junit.internal.runners.JUnit38ClassRunner.run(JUnit38ClassRunner.java:79)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)
Caused by: org.hibernate.HibernateException: Wrong column type in asd.entity_one for column ENTITY_TWO_ID. Found: double, expected: bigint
at org.hibernate.mapping.Table.validateColumns(Table.java:284)
at org.hibernate.cfg.Configuration.validateSchema(Configuration.java:1116)
at org.hibernate.tool.hbm2ddl.SchemaValidator.validate(SchemaValidator.java:139)
at org.hibernate.impl.SessionFactoryImpl.(SessionFactoryImpl.java:349)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1327)
at org.hibernate.cfg.AnnotationConfiguration.buildSessionFactory(AnnotationConfiguration.java:867)
at org.hibernate.ejb.Ejb3Configuration.buildEntityManagerFactory(Ejb3Configuration.java:669)
… 24 more

The code for the two entities is as follows:

@Entity
public class EntityOne 
{
@OneToOne(cascade = CascadeType.ALL, targetEntity = EntityTwo.class)
@JoinColumn(name = "ENTITY_TWO_ID")
private EntityTwo entityTwo;

... 
}


@Entity
public class EntityTwo
{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ELEMENT_ID")
private Long element_id;

...
}

Can someone please tell me what is wrong with my model?
Thanks in advance.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:40:45+00:00Added an answer on May 14, 2026 at 1:40 am

    Well, the message is self-explaining: the column type doesn’t match the type used at the Java level. If you want to sore a Long, use a BIGINT as column type.

    Update: I tested your code with Hibernate as JPA provider and ENTITYONE.ENTITY_TWO_ID is generated as a BIGINT column. Maybe you generated your table and changed the Java type later without regenerating the physical model. My suggestion would be to drop the table and to try again.

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