Question

i have a problem when it comes to retrieving value from jQuery to php.i was able to get the value of my select and pass it to my php but i can’t pass it back to php. here is the code…

 <script>
  $(document).ready(function()
  {
       $("select#months").change(function(event)
       {
         var m=$(this).val();
          $.ajax({
               type: 'POST',
           url: "monthly_CRD.php",
           data: {m: m},
               success: function(){alert("updated")}
    });
       });
  });
</script>   


<div>
<select id="months">
  <option value='00'>Month...</option>
      <option value='01'>Jan</option>
      <option value='02'>Feb</option>
      <option value='03'>Mar</option>
      <option value='04'>Apr</option>
    </select>
    <select id="years">
    <?php
     for($yr=10; $yr<=$year; $yr++)
{
    echo "<option value='".$yr."'>".$years[$yr]."</option>";
}
?>
   </select>
</div>
<?php
 if (isset($_POST['m'])) 
 {
        $m = $_POST['m'];
        echo $m;
 } else   {echo "fail";} 

?>

it keeps on returning fail which means that isset is not working.

Answer 1

If you mean that on page load, it returns fail, that is because on page load your $_POST array is probably empty.

If you want to know what was returned from your AJAX post, you need your success function to accept a parameter (like data) that jQuery will fill with the response to your post.
Then in the function body, you can write it to the DOM or your error console.