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Home/ Questions/Q 7642189
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T09:07:35+00:00 2026-05-31T09:07:35+00:00

I have a problem where the :eq() does not accept the counter, n ,

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I have a problem where the :eq() does not accept the counter, n, to insert values to a new column to the table in the HTML.

$(document).ready(function() {  
    var $tablerow = $('table.table').find('tr');
    count = 0;

    $tablerow.each(function(index, value){
        count += 1;
        var $listitem = $(this);
        n = parseInt($listitem.index());
        var $newRow = $("<td>" + n + "</td>");
        $("table.table tr:eq(n)").append($newRow);
    });
});  

HTML

<table class="table">
    <tr><td>First row</td></tr>
    <tr><td>second row</td></tr>
    <tr><td>third row</td></tr>
    <tr><td>fourth row</td></tr>
    <tr><td>fifth row</td></tr>
    <tr><td>sixth row</td></tr>
    <tr><td>seventh row</td></tr>
    <tr><td>eighth row</td></tr>
</table>
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  1. Editorial Team
    Editorial Team
    2026-05-31T09:07:36+00:00Added an answer on May 31, 2026 at 9:07 am

    Written as-is, you’re doing nothing more than writing a literal character, ‘n’, into .eq() method. Try this:

    $("table.table tr:eq(" + n + ")").append($newRow);
    
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