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Asked: May 10, 20262026-05-10T22:23:29+00:00 2026-05-10T22:23:29+00:00

I have a problem with a bash script. I have to use the operator

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I have a problem with a bash script. I have to use the operator * to multiplicate. Instead the script bugs me with expansion and using as operator the name of the script itself. I tried with single quotes but it doesn’t work 🙁 Here’s the code

#!/bin/bash -x  # Bash script that calculates an arithmetic expression # NO PRECEDENCE FOR OPERATORS # Operators: + - *   if [ '$#' -lt '3' ] then      echo 'Usage: ./calcola.scr <num> <op> <num> ...'     exit 1 fi  result=0 op=+ j=0  for i in '$@' do     if [ '$j' -eq '0' ]     then         # first try         #result=$(( $result $op $i ))           # second try         let 'result$op=$i'          j=1     else         op=$i         j=0     fi done  echo 'Result is $result'  exit 0 
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  1. 2026-05-10T22:23:30+00:00Added an answer on May 10, 2026 at 10:23 pm

    If ‘op’ is ‘*’, it will be expanded by the shell before your script even sees it. You need to choose something else for your multiplication operator, like ‘x’, or force your users to escape it by putting it in single quotes or preceeding it with a backslash.

    If the terms of the exercise allow it, maybe you should try using ‘read’ to get the expression from standard input instead of getting them from the command line.

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