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Home/ Questions/Q 8885075
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T21:13:13+00:00 2026-06-14T21:13:13+00:00

I have a problem with boolean for while loop. As such, I switch to

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I have a problem with boolean for while loop. As such, I switch to for loop instead.
But still, I cannot change the value of a boolean after the condition is met.

doFirst= true
    for (( j=1; j<=7; j++))
    do
            letter="A"
            seatChoses=$letter$j

            flagRand=$(echo $flightSeatBooked | awk -v flseatRand=$flightSeatBooked -v orseatRand=$seatChoses '{print match(flseatRand, orseatRand)}')
            if  $doFirst ; then
            **$doFirst= false** // Here is the error!
                if [ $flagRand -eq 0 ]; then
                    echo "System generated a slot, "$seatChoses" for you. [Y or N]"
                fi
            fi

    done
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  1. Editorial Team
    Editorial Team
    2026-06-14T21:13:15+00:00Added an answer on June 14, 2026 at 9:13 pm

    There is no such thing as a boolean value in a shell script (that is, something you can store in a variable, and treat as a boolean). true and false are commands; true exits with value 0, and false exits with a nonzero value. An if statement in bash taks a command; if that command returns 0, then the then clause is executed, otherwise the else clause is.

    doFirst= true
    

    This line doesn’t do what you expect at all. In a shell script, you cannot have any spaces after the equals sign. The space means you’re done with the assignment, and now writing a command. This is equivalent to:

    doFirst="" true
    

    Furthermore, if you have an assignment before a command (like this), that doesn’t actually perform the assignment in the shell. That sets that environment variable in the environment for that command alone; the assignment has no effect on anything outside of that command.

    if  $doFirst ; then
    

    This expands the $doFirst variable, and tries to interpret the result as a command. Oddly, if $doFirst is undefined (which it is, as I explain above), this takes the then branch. At that point, you make your first mistake again, trying to set a variable to be false, and again, nothing happens; $doFirst is left undefined. You make the further mistake of trying to assign $doFirst; you use $ to get the value of a variable, when setting, you use the bare name.

    My recommendation would be to not try to use booleans in Bash; just use strings instead, and check the value of the string. Note that I remove the space, so now I’m setting it to that exact string; and there is no command, so this sets the variable within the shell, not in the environment for a single command:

    doFirst=true
    # ...
       if [ $doFirst = true ]; then
           doFirst=false
       # ...
    
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