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Home/ Questions/Q 1007011
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T08:33:08+00:00 2026-05-16T08:33:08+00:00

I have a problem with jQuqeryUI. I would like to run some code whenever

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I have a problem with jQuqeryUI.
I would like to run some code whenever an element is dragged and dropped on an invalid target.
As far as I can see, there is no predefined event for this, but I have thought about combining information from following events: over, out, remove and stop, to achieve this. However that might sound like it’s going to be a mess, is there a cleaner way yo do it?

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  1. Editorial Team
    Editorial Team
    2026-05-16T08:33:09+00:00Added an answer on May 16, 2026 at 8:33 am

    You can pass a method to the revert option as well, for example if we take the example demo like this:

    <div id="draggable" class="ui-widget-content">
        <p>I revert when I'm not dropped</p>
    </div>
    <div id="droppable" class="ui-widget-header">
        <p>Drop me here</p>
    </div>​
    

    Then on your draggable you can calculate whether to revert, like this:

    $("#draggable").draggable({ 
        revert:  function(dropped) {
           var dropped = dropped && dropped[0].id == "droppable";
           if(!dropped) alert("I'm reverting, what a cruel world!");
           return !dropped;
        } 
    });
    

    You can give it a try here, the dropped parameter passed in is the element it was dropped on that’s a .droppable(), it’s just false if it landed anywhere else.

    Or if you’re using the accept option you may want to calculate off that, like this:

    var dropped = dropped && $(this).is(dropped.droppable('option', 'accept'));
    

    This uses the accept selector and uses .is() to see if the droppable matches.

    You can view a demo of that here.

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