Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 549269
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T11:09:59+00:00 2026-05-13T11:09:59+00:00

I have a problem with my hibernate mapping using EmbeddedId. My code looks like

  • 0

I have a problem with my hibernate mapping using EmbeddedId. My code looks like these:

Inventory:

public class Inventory {

private Long id;

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "inventory_id")
public Long getId() {
    return id;
}

public void setId(Long id) {
    this.id = id;
}

private Set<InventoryUser> inventoryUser = new HashSet<InventoryUser>();

@OneToMany(cascade = CascadeType.PERSIST, fetch = FetchType.EAGER, mappedBy = "pk.inventory")
public Set<InventoryUser> getInventoryUser() {
    return inventoryUser;
}

public void setInventoryUser(Set<InventoryUser> productUser) {
    this.inventoryUser = productUser;
}
}

User:

@Entity
@Table(name = "User_Table")
public class User implements Comparable{
private String id;

@Id
@Column(name = "user_id")
public String getId() {
    return id;
}

public void setId(String id) {
    this.id = id;
}

private Set<InventoryUser> inventoryUser = new LinkedHashSet<InventoryUser>();

@OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.user")
public Set<InventoryUser> getInventoryUser() {
    return inventoryUser;
}

public void setInventoryUser(Set<InventoryUser> inventoryUser) {
    this.inventoryUser = inventoryUser;
}

InventoryUser

@Entity
@Table(name = "Inventory_User")
public class InventoryUser {    
private ProductUserPK pk = new ProductUserPK();

@EmbeddedId
@NotNull
public ProductUserPK getPk() {
    return pk;
}

public void setPk(ProductUserPK pk) {
    this.pk = pk;
}

@Embeddable
public static class ProductUserPK implements Serializable {
    public ProductUserPK(){

    }

    private User user;

    @ManyToOne
    @JoinColumn(name = "user_id", insertable = false, nullable = false)
    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
        // this.user.getInventoryUser().add(InventoryUser.this);

    }

    private Inventory inventory;

    @ManyToOne
    @JoinColumn(name = "inventory_id", insertable = false, nullable = false)
    public Inventory getInventory() {
        return inventory;
    }

    public void setInventory(Inventory inventory) {
        this.inventory = inventory;

    }

Now persisting data works fine, but when I search for Inventories I always get a StackOverflow, even if there is only one entry in DB.

Any ideas what this is about?

Greets
Chris

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T11:10:00+00:00Added an answer on May 13, 2026 at 11:10 am

    I think it’s because of the circular reference between InventoryUser and ProductUserPK.

    Either InventoryUser.pk or ProductUserPK.user should be lazy.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 394k
  • Answers 394k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer SELECT c.* FROM Comments AS c JOIN Comments AS tr… May 15, 2026 at 2:12 am
  • Editorial Team
    Editorial Team added an answer It should never happen. $data gets purified somewhere between var_dumps.… May 15, 2026 at 2:12 am
  • Editorial Team
    Editorial Team added an answer I would think DirectX would be a better... .NET Video… May 15, 2026 at 2:12 am

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.