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Home/ Questions/Q 8769303
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T17:18:23+00:00 2026-06-13T17:18:23+00:00

I have a problem with PlayFramework 1.2.5 and my question is: How can I

  • 0

I have a problem with PlayFramework 1.2.5 and my question is:

How can I use a variable that be assigned by a #set{…/} tag into a #{if …/} tag?

This is my java code – (it works):

...
renderArgs.put("blockInsert", true);
...

And this is my htm code – (it works):

...
#{set allowInsert:"${!blockInsert}" /}
...

Reading variables with ${} and #{get/} – (it works):

blockInsert == ${blockInsert}<br/>
allowInsert == #{get 'allowInsert' /}<br/>

Using variables on #{if/} tag – (it not works well):

using variable from renderArgs - (it works) 
#{if blockInsert}
    cant't insert
#{/if}
#{else}
    can insert
#{/else} 
<br/>

using variable from #{set} tag - (it not works) 
#{if allowInsert}
    can insert
#{/if}
#{else}
    cant't insert
#{/else}
...

When I run this page the output is:

blockInsert == true
allowInsert == false 

using variable from renderArgs - (it works) cant't insert 
using variable from #set} tag - (it not works) can insert 
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  1. Editorial Team
    Editorial Team
    2026-06-13T17:18:24+00:00Added an answer on June 13, 2026 at 5:18 pm

    use

    %{allowInsert=!blockInsert}%
    

    instead of set.
    The Result of the set tag is a String. Or you adjust the if statement:

    #{if allowInsert == "true"}
        can insert
    #{/if}
    #{else}
        cant't insert
    #{/else}
    
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