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Home/ Questions/Q 9082983
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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T20:40:43+00:00 2026-06-16T20:40:43+00:00

I have a problem with returning data from ajax to caller function. When I’m

  • 0

I have a problem with returning data from ajax to caller function. When I’m console.logging it out it’s undefined.

I believe my problem occurs due the fact that js is asynchronous, and when I’m console.logging the data out it’s not ready yet. What can I do to solve it?

FooFunction: function(userInput){

    var fooData = FooFunction2(userInput);
    console.log(fooData);     // <--- undefined
},

FooFunction2: function(userInput) {

    $.ajax({
         url:'./php/test.php',
         type:'post',
         dataType:'json',
         data:{ 
             fooData: userInput
         },
         success:function(data) {
             ...manipulating the data...

             console.log(manipulatedData);    // <--- ['foo', 'foo2'];
             return manipulatedData;
         }
    });
},
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-16T20:40:44+00:00Added an answer on June 16, 2026 at 8:40 pm

    The ajax call is asynchronous, so returning will not work. Change your code to use a callback that is invoked when the ajax call has completed.

    I changed your code to do that:

    FooFunction: function(userInput){
        var callbackfunc = function(ajaxData)
        {
            console.log(ajaxData); //ajax is complete!
        };
    
        this.FooFunction2(userInput, callbackfunc);
    },
    
    FooFunction2: function(userInput, callbackfunc) {
    
        $.ajax({
             url:'./php/test.php',
             type:'post',
             dataType:'json',
             data:{ 
                 fooData: userInput
             },
             success:function(data) {
                 ...manipulating the data...
    
                 console.log(manipulatedData);    // <--- ['foo', 'foo2'];
                 callbackfunc(manipulatedData);
             }
        });
    },
    
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