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Home/ Questions/Q 7621219
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T04:08:33+00:00 2026-05-31T04:08:33+00:00

I have a problem with some jquery please see below code. I have 2

  • 0

I have a problem with some jquery please see below code.

I have 2 events running. What I am trying to achieve is when the first event is completely finishes then I want to run second event.

First event

$("#brand div").each(function(e) {
$(this).delay(600*e).fadeTo('slow',1)
})

Second event

$(".b-circle-image a").each(function(ev) {
$(this).delay(600*ev).fadeTo('slow',1);
})

I even tried like this using status = false; but still doesn’t work.

    var checkStatus  = true;
    $("#brand div").each(function(e) {//Display segments in order
      $(this).delay(600*e).fadeTo('slow',1)
      checkStatus = false;
    })
    if(!checkStatus==false){
      $(".b-circle-image").show();
      $(".b-circle-image a").each(function(ev) {//Display circle image in order
      $(this).delay(600*ev).fadeTo('slow',1);
    })
    }

If any one has any idea about this would be much appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T04:08:35+00:00Added an answer on May 31, 2026 at 4:08 am
    // You can create deferred object for each fadeTo and resolve it on complete animation callback.
    var firstEvent = $("#brand div").map(function(i, el) {
        var dfd = $.Deferred();
        $(el).delay(600*i).fadeTo('slow', 0, function() {
            dfd.resolve();
        })
        return dfd;
    });
    // Then use $.when function (http://api.jquery.com/jQuery.when/)
    $.when.apply(this, firstEvent).done(function() {
        $(".b-circle-image a").each(function(i) {
            $(this).delay(600*i).fadeTo('slow',0);
        });
    });
    
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