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Home/ Questions/Q 7026813
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:10:00+00:00 2026-05-28T00:10:00+00:00

i have a problem with this homepage. I have to create a Site like

  • 0

i have a problem with this homepage.

I have to create a Site like this:

status   create work finished

Item1    *       o      o
Item2    o       *      o
Item3    o       o      *

(* = checked, o = unchecked)

Now as admin i have the rights to change the status of the each Item.

For example when i change the Status from Item1 to “work” it should send a Form and update it in Database.

My Problem is know, should i create for each pair of 3 radiobuttons 1 Form?

But when i create 1 for all Buttons i will have problems to know which status have changed.
Only compare with each Database entry.

Before someone ask, i should use radiobuttons.
Hope someone could help.

Greetz

Demonking

Edit: Sorry, eomeone have misunderstand me.
I meant if i would be faster and better with :

<form method="post">
 Item 1 <input type="radio" name="item1" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="finished" onclick="this.form.submit()"/>
</form>

<form method="post">
 Item 2 <input type="radio" name="item2" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="finished" onclick="this.form.submit()"/>
</form>

or

<form method="post">
 Item 1 <input type="radio" name="item1" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="finished" onclick="this.form.submit()"/>
 Item 2 <input type="radio" name="item2" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="finished" onclick="this.form.submit()"/>


</form>

because of Performance with PHP/MySQL

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:10:01+00:00Added an answer on May 28, 2026 at 12:10 am

    I’d probably use one form and then perform a database update for all values.
    And then I’d use javascript to augment the page, i.e. keep it working for clients that don’t support/execute javascript but have a submit-handler that only sends values that have changed in clients that do execute javascript.
    And then I’d do some benchmarking/profiling to check if the “only changed values” versionn really is faster/better than the “update all values” version. If not the javascript part is history 😉

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