Question

I have a problem with this method. It does not output the correct search when the user asks for it.

Here is my code:

System.out.println("Search by Email.");
Employee employeeSearchEmail = MenuMethods.userInputByEmail();
Store.searchByEmail(employeeSearchEmail.getEmployeeEmail());

public Employee searchByEmail(String employeeEmail) {
    for (Employee employee : map.values()) {
        System.out.println(employee);
        map.equals(getClass());
        map.equals(employee.getEmployeeEmail());
        employee = new Employee(employeeEmail);
        ;
        return employee;
    }
    return null;
}

public static Employee userInputByEmail() {
    // String temp is for some reason needed. If it is not included
    // The code will not execute properly.
    String temp = keyboard.nextLine();
    Employee e = null;
    System.out.println("Please enter the Employee Email:");
    String employeeEmail = keyboard.nextLine();
    // This can use the employeeName's constructor because java accepts the
    // parameters instead
    // of the name's.
    return e = new Employee(employeeEmail);

}

Answer 1

problem is that there is no if condition in your program like this :

public Employee searchByEmail(String employeeEmail) {
        for (Employee employee : map.values()) {
            map.equals(getClass());
            if (map.equals(employee.getEmployeeEmail())){
                System.out.println(employee);
                return employee;
            }
        }
        return null;
    }

this line :
System.out.println(employee);

it will print employee object until it finds the match and when match it will return that employee object..