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Home/ Questions/Q 610083
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T17:38:13+00:00 2026-05-13T17:38:13+00:00

i have a problem with this mysql query. It take vmore as 1 day

  • 0

i have a problem with this mysql query. It take vmore as 1 day to execute …

The query is :

INSERT INTO traduction  
(traduction.`id`,traduction.`traduction`,traduction.`language`,traduction.`type`) 
(
 SELECT cities.id,cities.name, '', 'city' FROM cities 
  WHERE cities.id NOT IN 
   (
    SELECT traduction.`id` FROM traduction WHERE traduction.type='city' GROUP BY id
   )
);

I made a explain extended on the 2 select and it says DEPENDENT SUBQUERY so the second select is played for every select on cities but I think it’s useless.

There is a way in mysql or another sql server which can allow that ?

Or maybe a complet other query.

The idea is, if a city doesn’t have a traduction, the city name should be writen in the traduction table. Then I just have to look in traduction table and not city table.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T17:38:13+00:00Added an answer on May 13, 2026 at 5:38 pm

    You can try something like this

    INSERT INTO traduction   
    (traduction.`id`,traduction.`traduction`,traduction.`language`,traduction.`type`)  
    ( 
    SELECT  cities.id,
            cities.name, 
            '', 
            'city' 
    FROM    cities  LEFT JOIN
            (
                SELECT  traduction.`id` 
                FROM    traduction 
                WHERE   traduction.type='city' 
                GROUP BY id 
            ) s ON cities.id = s.id
    WHERE   s.ID IS NULL
    );
    

    Also ensure that you have the correct indexes on your tables, for lets say traduction.type or traduction.id and cities.id

    INSERT INTO traduction   
    (traduction.`id`,traduction.`traduction`,traduction.`language`,traduction.`type`)  
    ( 
    SELECT  cities.id,
            cities.name, 
            '', 
            'city' 
    FROM    cities  LEFT JOIN
            (
                SELECT  DISTINCT
                        traduction.`id` 
                FROM    traduction 
                WHERE   traduction.type='city'
            ) s ON cities.id = s.id
    WHERE   s.ID IS NULL
    );
    

    EDIT: NOT EXISTS

    INSERT INTO traduction    
    (traduction.`id`,traduction.`traduction`,traduction.`language`,traduction.`type`)   
    (  
    SELECT  cities.id, 
            cities.name,  
            '',  
            'city'  
    FROM    cities 
    WHERE   NOT EXISTS (
                            SELECT  DISTINCT 
                                    traduction.`id`  
                            FROM    traduction  
                            WHERE   traduction.type='city'
                            AND     cities.id = traduction.id 
                        )
    );
    
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