Question

I have a problem with this simple program because it doesnt give me the true outcome. I just want to sum two arguments in the first function and then use the outcome in the second one. It will be nice to have overall outcome in the main function. Also I would like to ask the same question with arrays.

#include <stdio.h>
#include <stdlib.h>

int sum()
{
int a=2;
int b=3;
int s=a+b;
printf("sum=%d\n",s);
return s;
}

int sum2(int s)
{
int c=5;
int d=c+s;

}


int main(int s,int d)
{
sum();

printf("sum=%d\n",s);

printf("sum2=%d\n",d);

getchar();
return 0;
}

Answer 1

You can’t access the value of variable ‘s’ outside the function sum() since it is out of scope. You’ll have to return the value to your main() function. Also your main function parameters are incorrect. You need something more like this:

#include <stdio.h>
#include <stdlib.h>

int sum(int a, int b)
{
    int s=a+b;
    printf("sum=%d\n",s);
    return s;
}

int sum2(int c, int sum)
{
    return c+sum;
}


int main(int argc, char *argv[])
{
    int val1 = sum(2, 3);
    printf("sum=%d\n",val1);

    int val2 = sum2(5, val1);
    printf("sum2=%d\n", val2);

    getchar();
    return 0;
}