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Home/ Questions/Q 7865155
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T00:00:00+00:00 2026-06-03T00:00:00+00:00

I have a program in which I wanted to remove the spaces from a

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I have a program in which I wanted to remove the spaces from a string. I wanted to find an elegant way to do so, so I found the following (I’ve changed it a little so it could be better readable) code in a forum:

char* line_remove_spaces (char* line)
{
    char *non_spaced = line;
    int i;
    int j = 0;
    for (i = 0; i <= strlen(line); i++)
    {
        if ( line[i] != ' ' )
        {
            non_spaced[j] = line[i];
            j++;
        }
    }
    return non_spaced;
}

As you can see, the function takes a string and, using the same allocated memory space, selects only the non-spaced characters. It works!

Anyway, according to Wikipedia, a string in C is a “Null-terminated string“. I always thought this way and everything was good. But the problem is: we put no “null-character” in the end of the non_spaced string. And somehow the compiler knows that it ends at the last character changed by the “non_spaced” string. How does it know?

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  1. Editorial Team
    Editorial Team
    2026-06-03T00:00:01+00:00Added an answer on June 3, 2026 at 12:00 am

    This does not happen by magic. You have in your code:

    for (i = 0; i <= strlen(line); i++)
                  ^^
    

    The loop index i runs till strlen(line) and at this index there is a nul character in the character array and this gets copied as well. As a result your end result has nul character at the desired index.

    If you had

    for (i = 0; i < strlen(line); i++)
                  ^^
    

    then you had to put the nul character manually as:

    for (i = 0; i < strlen(line); i++)
    {
        if ( line[i] != ' ' )
        {
            non_spaced[j] = line[i];
            j++;
        }
    }
    // put nul character
    line[j] = 0;
    
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