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Home/ Questions/Q 584417
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:53:44+00:00 2026-05-13T14:53:44+00:00

I have a program like this public class no_of_letters_count { static int i; public

  • 0

I have a program like this

public class no_of_letters_count {
static int i;
 public static void main(String[] args) 
 {

  String sMessage="hello how r u";
  String saMessage[] = sMessage.split("");
  List sList = Arrays.asList(saMessage);                  
  Collections.sort(sList);
  Iterator i=sList.iterator();
  while (i.hasNext())
  {
   System.out.println((String)i.next());
  }
 }
}

//Now i want to count the number of occurance of each characters.

Like

Count of h=2

Count of e=1

and so on

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:53:44+00:00Added an answer on May 13, 2026 at 2:53 pm

    Iterate over sList and put each char in a HashMap. If it doesn’t exists start with count 1, otherwise increment the count.

    EDIT : Cannot help posting some code.

    First of all, use gnerics.

    List<Character> sList = Arrays.asList(saMessage.toCharArray()); 
    

    Then use the following map :

    Map<Character, Integer> cmap = new HashMap<Character, Integer>();
    
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