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Asked: 2026-05-11T11:15:07+00:00

I have a project that includes 49 folders, each one has a file called

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I have a project that includes 49 folders, each one has a file called index.php

All index.php files are almost the same except for one part that changes depending on the folder it is in.

<?php include_once('/home/bgarch/public_html/galleryheader.html'); ?> <?php include_once('/home/bgarch/public_html/culture/loadscripts.html'); ?>  </head> <body>   <div class='header'>     <?php include_once('/home/bgarch/public_html/header.html'); ?> </div>  <div class='clear'></div>  <div class='displaywrapper'>     <?php include_once('content.html'); ?> </div></div>      <div class='clear'></div>  <?php include_once('/home/bgarch/public_html/footer.html'); ?>

In the second line where the above reads: ‘../culture/..’ the word culture is the variable and is different based on the folder it is in.

What I need to do know is do a ‘Find/Replace all in project’ that automatically replaces all the text inside each ‘index.php’ file with the following’

<?php include_once('http://www.bgarchitect.co.nz/subPage/index.php'); ?>

I have spent the past 2 hours trying to figure out regular expressions to acomplish this but have been unsuccessful so far. Maybe it is not possible to do so?

Anyway, I thought I’d ask a question here in hopes it is in fact much easier than I anticipated. So any help/pointer/hints or tricks are much appreciated.

Thanks for reading, Jannis

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1 Answer

  1. If I understood right, you want to replace the word culture (which is the current directory) with the word subPage?

    You can do this with the help of TextMate bundles.

    Bundles > Bundle editor > Edit commands, than add a New command. Add this as a command. I think it does what you want. You have to set the input to the command as Entire document and the output to Replace document.

    #!/bin/bash  sed 's/'${TM_DIRECTORY##*/}'/theWordYouWanToReplaceTheDirWith/g' | cat
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