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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T21:32:31+00:00 2026-05-15T21:32:31+00:00

I have a Python class that have attributes named: date1, date2, date3, etc. During

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I have a Python class that have attributes named: date1, date2, date3, etc.

During runtime, I have a variable i, which is an integer.

What I want to do is to access the appropriate date attribute in run time based on the value of i.

For example,

if i == 1, I want to access myobject.date1

if i == 2, I want to access myobject.date2

And I want to do something similar for class instead of attribute.

For example, I have a bunch of classes: MyClass1, MyClass2, MyClass3, etc. And I have a variable k.

if k == 1, I want to instantiate a new instance of MyClass1

if k == 2, I want to instantiate a new instance of MyClass2

How can i do that?

EDIT

I’m hoping to avoid using a giant if-then-else statement to select the appropriate attribute/class.

Is there a way in Python to compose the class name on the fly using the value of a variable?

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  1. Editorial Team
    Editorial Team
    2026-05-15T21:32:31+00:00Added an answer on May 15, 2026 at 9:32 pm

    You can use getattr() to access a property when you don’t know its name until runtime:

    obj = myobject()
    i = 7
    date7 = getattr(obj, 'date%d' % i) # same as obj.date7
    

    If you keep your numbered classes in a module called foo, you can use getattr() again to access them by number.

    foo.py:
      class Class1: pass
      class Class2: pass
      [ etc ]
    
    
    bar.py:
      import foo
      i = 3
      someClass = getattr(foo, "Class%d" % i) # Same as someClass = foo.Class3
      obj = someClass() # someClass is a pointer to foo.Class3
      # short version:
      obj = getattr(foo, "Class%d" % i)()
    

    Having said all that, you really should avoid this sort of thing because you will never be able to find out where these numbered properties and classes are being used except by reading through your entire codebase. You are better off putting everything in a dictionary.

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