Question

I have a python dictionary that I want to sort according to name:

location_map_india = {
  101: {'name': 'Andaman & Nicobar Islands', 'lat': 11.96, 'long': 92.69, 'radius': 294200},  
  108: {'name': 'Andhra Pradesh', 'lat': 17.04, 'long': 80.09, 'radius': 294200},
...
}

It doesn’t come out the way I expect it. I tried:

location_map_india = sorted(location_map_india.iteritems(), key=lambda x: x.name)

The above didn’t work. What should I do?

Update

The following was allowed and behaved as expected. Thanks for all the help.
Code:

location_map_india = sorted(location_map_india.iteritems(), key=lambda x: x[1]["name"])

Template:

{% for key,value in location_map_india %}<option value="{{key}}" >{{value.name}}</option>{% endfor %}

Answer 1

You are close. Try:

location_map_india = sorted(location_map_india.iteritems(), key=lambda x: x[1]["name"])

but the result would be a list not a dict. dict is orderless.