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Home/ Questions/Q 7704151
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T23:37:18+00:00 2026-05-31T23:37:18+00:00

I have a Python list of predefined integers: intvals = [5000, 7500, 10000, 20000,

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I have a Python list of predefined integers:

intvals = [5000, 7500, 10000, 20000, 30000, 40000, 50000]

I need to round down and up to the next lower/higher value in the list. So for example, given the number 8000, the result should be [7500, 10000]. For 42000, it should be [40000, 50000]. I am wondering if there is an easy way to do it.

My idea would be to create a function that has two loops – one that decreases a value -1 until it finds one in the list, and one that increases the value by 1 until it finds the higher match. This would work but maybe there is a better solution?

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  1. Editorial Team
    Editorial Team
    2026-05-31T23:37:20+00:00Added an answer on May 31, 2026 at 11:37 pm

    This is perfect for bisect.bisect_right() and bisect.bisect_left().

    Here is some example code for which you can expand on:

    import bisect
    
    def get_interval(x):
        intvals = [5000, 7500, 10000, 20000, 30000, 40000, 50000]
        i = bisect.bisect_right(intvals,x)
        return intvals[i-1:i+1]
    
    print get_interval(5500)
    
    """
    >>>
    [5000, 7500]
    """
    

    This technique is fast as it uses binary search (so logN instead of N lookups)

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