Question

I have a QList<float**>. I first iterate on elements to work with them:

for( int i = 0 ; i < nb ; i++ )
{
    float** data1 = data_list.at( i ) ;
    float** data2 = data_list.at( i + 1 ) ;
    // do things with data1 and data2

}

What happens if I delete[] in a C-stylish manner data1 and data2 inside this loop? Are elements at position i and i+1 in data_list destroyed as well (so that i cannot access them anymore) ?

Answer 1

it is a list of float**. The float* they are pointing to are not in the list.
which means if you use delete[], the memory is released, but data_list itself doesnt change. After this point they will be invalid pointers.