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Home/ Questions/Q 7158877
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T13:08:20+00:00 2026-05-28T13:08:20+00:00

i have a qt form that has a multiplication problem and 4 buttons. the

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i have a qt form that has a multiplication problem and 4 buttons. the 4 buttons (choices) are randomly generated and so is the question.

i just want to randomize the 4 choices so they are random but none of them are equivalent to the other choices. this is how i am doing it right now, but it’s not working very well:

while (choice1 == choice2 || choice1 == choice3 || choice1 == choice4)
    choice1 = (rand() % max) + 1;
while (choice2 == choice1 || choice2 == choice3 || choice2 == choice4)
    choice2 = (rand() % max) + 1;
while (choice3 == choice1 || choice3 == choice2 || choice3 == choice4)
    choice3 = (rand() % max) + 1;
while (choice4 == choice1 || choice4 == choice2 || choice4 == choice3)
    choice4 = (rand() % max) + 1;

does anyone else have a better way?

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  1. Editorial Team
    Editorial Team
    2026-05-28T13:08:20+00:00Added an answer on May 28, 2026 at 1:08 pm

    Since the number of elements is fixed and very small, your overall approach is pretty reasonable. However, the implementation is buggy.

    Here is how it can be fixed:

    choice1 = (rand() % max) + 1;
    do { choice2 = (rand() % max) + 1; } while (choice2 == choice1);
    do { choice3 = (rand() % max) + 1; } while (choice3 == choice1 || choice3 == choice2);
    do { choice4 = (rand() % max) + 1; } while (choice4 == choice1 || choice4 == choice2 || choice4 == choice3);
    

    There are better ways to do this if one needs a larger number of elements, or if the number of elements is variable.

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