Question

I have a query in Oracle for a report that looks like this:

SELECT TRUNC (created_dt) created_dt
    ,  COUNT ( * ) AllClaims
    ,  SUM(CASE WHEN filmth_cd in ('T', 'C') THEN 1 ELSE 0 END ) CT
    ,  SUM(CASE WHEN filmth_cd = 'W' THEN 1 ELSE 0 END ) Web 
    ,  SUM(CASE WHEN filmth_cd = 'I' THEN 1 ELSE 0 END ) Icon 
FROM claims c
WHERE c.clsts_cd NOT IN ('IN', 'WD')
   AND  TRUNC (created_dt) between 
    to_date('1/1/2006', 'dd/mm/yyyy') AND 
    to_date('1/1/2100', 'dd/mm/yyyy')
GROUP BY TRUNC (created_dt)
ORDER BY TRUNC (created_dt) DESC;

It returns data like this:

Create_Dt  AllClaims   CT    Web    Icon
1/26/2011  675         356   285    34
1/25/2011  740         322   379    39
...

What I need is a result set that sums all of the daily values into a weekly value. I am pretty new to PL/SQL and not sure where to begin.

Answer 1

Something like

SELECT TRUNC (created_dt, 'IW') created_dt
    ,  COUNT ( * ) AllClaims
    ,  SUM(CASE WHEN filmth_cd in ('T', 'C') THEN 1 ELSE 0 END ) CT
    ,  SUM(CASE WHEN filmth_cd = 'W' THEN 1 ELSE 0 END ) Web 
    ,  SUM(CASE WHEN filmth_cd = 'I' THEN 1 ELSE 0 END ) Icon 
FROM claims c
WHERE c.clsts_cd NOT IN ('IN', 'WD')
   AND  TRUNC (created_dt) between 
    to_date('1/1/2006', 'dd/mm/yyyy') AND 
    to_date('1/1/2100', 'dd/mm/yyyy')
GROUP BY TRUNC (created_dt, 'IW')
ORDER BY TRUNC (created_dt, 'IW') DESC;

will aggregate the data based on the first day of the ISO week.