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Home/ Questions/Q 7757877
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T13:12:33+00:00 2026-06-01T13:12:33+00:00

I have a query like this SELECT TOWN, NAME FROM CINEMA WHERE CITY_ID =

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I have a query like this

SELECT TOWN, NAME FROM CINEMA WHERE CITY_ID = ".$_POST['country']." GROUP BY TOWN, NAME

In view side, I take the values with the help of template_lite

   <table border="1" >
        <br />
 {foreach value=mp from=$mpbycity}
 <tr><td>{$mp.TOWN}</td></tr>
  <tr><td>{$mp.NAME}</td></tr>

 {/foreach}
    </table>

The problem is the duplicates.You can see from below pic.

I tried array_unique but it does not work.

enter image description here

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  1. Editorial Team
    Editorial Team
    2026-06-01T13:12:35+00:00Added an answer on June 1, 2026 at 1:12 pm

    First, you must filter variable before writing inside query ..CITY_ID = ".$_POST['country'].". With this code attacker can inject code on query. Check Sql injection. To avoid this use mysql_real_escape_string().

    ..CITY_ID = ".mysql_real_escape_string($_POST['country'])."...
    

    And to unique array, you can use array_unique(), SELECT DISTINCT, GROUP BY clauses. Also in loop can avoid to write duplicate values to array. All depends on your database structure and query.

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