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Home/ Questions/Q 580055
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:25:55+00:00 2026-05-13T14:25:55+00:00

I have a query string like the one given below: http://localhost/project/viewMember.php?sort=Y2xhc3M=&class=Mw==&page=9 Now variable: page

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I have a query string like the one given below:

http://localhost/project/viewMember.php?sort=Y2xhc3M=&class=Mw==&page=9

Now variable: page in query string can be anywhere within the query string either in beginning or middle or at end (like ?page=9 or &page=9& or &page=9).

Now, I need to remove page=9 from my query string and get a valid query string.

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:25:55+00:00Added an answer on May 13, 2026 at 2:25 pm

    Tried writing a function for this. Seems to work:

    <?php
    
    $url = "http://localhost/project/viewMember.php?sort=Y2xhc3M=&class=Mw==&page=9";
    // prints http://localhost/project/viewMember.php?sort=Y2xhc3M=&class=Mw==
    print changeURL($url) . "\n"; 
    
    $url = "http://localhost/project/viewMember.php?sort=Y2xhc3M=&page=9&class=Mw==";
    // prints http://localhost/project/viewMember.php?sort=Y2xhc3M=&class=Mw==
    print changeURL($url) . "\n";
    
    function changeURL($url)
    {
        $arr = parse_url($url);
    
        $query = $arr['query'];
    
        $pieces = explode('&',$query);
    
        for($i=0;$i<count($pieces);$i++)
        {
                if(preg_match('/^page=\d+/',$pieces[$i]))
                     unset($pieces[$i]);
        }    
    
        $query = implode('&',$pieces);
    
        return "$arr[scheme]://$arr[host]$arr[user]$arr[pass]$arr[path]?$query$arr[fragment]";   
    }
    ?>
    
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