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Home/ Questions/Q 8646429
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T12:48:19+00:00 2026-06-12T12:48:19+00:00

I have a query that gets 5 lines of data like this example below

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I have a query that gets 5 lines of data like this example below

$query = "SELECT ref,user,id FROM table LIMIT 0, 5"; 
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
}

I want to run a query inside each results like this below

$query = "SELECT ref,user,id FROM table LIMIT 0, 5"; 
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
 $ref = $row['ref'];
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}

but for some reason it’s only display the first line when I add the query inside it. I can seem to make it run all 5 queries.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T12:48:20+00:00Added an answer on June 12, 2026 at 12:48 pm

    You change the value of your $query in your while loop.
    Change the variable name to something different.

    Ex:

    $query = "SELECT ref,user,id FROM table LIMIT 0, 5"; 
    $result = mysql_query($query) or die(mysql_error());
    while($row = mysql_fetch_array($result))
    {
     $ref = $row['ref'];
    $qry = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
    $rslt = mysql_query($qry) or die(mysql_error());
    if (mysql_num_rows($rslt) )
    {
    $title = $row['title'];
    } else {
    $title = "No Title";
    }
    echo "$ref - $tile";
    }
    
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