Question

I have a query that gives the right information back but I cannot figure out how to get distinct days and sum the count. below is my query and the results shows what I get back, and what I would like to have come back. I thought the union would join them and give my back the results that I wanted. I have search for quite some time and have not located any help on this topic. Any help will be appreciated. Thank you in advance.

SELECT COUNT(log_datetime) AS icount, CONVERT(varchar, log_datetime, 101) AS logdate
from openrowset('sqloledb', 'ServerName1';'UserID';'Password',
          'select * from DatabaseName..TableName where field1 > 899')
group by convert(varchar, log_datetime, 101)
union
SELECT COUNT(log_datetime) AS icount, CONVERT(varchar, log_datetime, 101) AS logdate
from openrowset('sqloledb', 'ServerName2';'UserID';'Password',
    'select * from DatabaseName..TableName where field1 > 899')
group by convert(varchar, log_datetime, 101)
order by logdate

Results
235     01/10/2013
312     01/10/2013
3091    01/11/2013
3197    01/11/2013
3339    01/12/2013
3536    01/12/2013

Wanted Results
547      01/10/2013
6288     01/11/2013
6875     01/12/2013

Answer 1

You can try this

SELECT SUM(icount) AS icount, logdate FROM
(
    SELECT COUNT(log_datetime) AS icount, CONVERT(varchar, log_datetime, 101) AS logdate
    FROM openrowset('sqloledb', 'ServerName1';'UserID';'Password',
              'select * from DatabaseName..TableName where field1 > 899')
    GROUP BY convert(varchar, log_datetime, 101)
        UNION ALL
    SELECT COUNT(log_datetime) AS icount, CONVERT(varchar, log_datetime, 101) AS logdate
    FROM openrowset('sqloledb', 'ServerName2';'UserID';'Password',
        'select * from DatabaseName..TableName where field1 > 899')
    GROUP BY convert(varchar, log_datetime, 101)
) AS tbl
GROUP BY logdate
ORDER BY logdate

And here is sqlfiddle